The short answer
Oxidation occurs at the anode and reduction at the cathode in every electrochemical cell. That never changes. What changes between galvanic and electrolytic cells is the sign convention on the electrodes, and that is the source of nearly all the confusion.
A galvanic (voltaic) cell runs a spontaneous redox reaction and produces electrical work. Its anode is negative. An electrolytic cell uses an external power supply to drive a non-spontaneous reaction. Its anode is positive.
If you hold those two facts together — the reaction assignment is fixed, the sign convention is not — most MCAT electrochemistry questions become bookkeeping.
What stays the same in both cells
Oxidation at the anode, reduction at the cathode. The standard mnemonics are worth keeping: "An Ox" (anode, oxidation) and "Red Cat" (reduction, cathode).
Electrons always travel through the external wire from the anode to the cathode. They are released by the oxidation half-reaction and consumed by the reduction half-reaction, so the direction is dictated by where each half-reaction sits.
Anions always migrate toward the anode and cations toward the cathode, within the solution. The names help: anions go to the anode, cations to the cathode.
So three things are constant across both cell types: the reaction at each electrode, the direction of electron flow in the wire, and the direction of ion migration in solution.
What changes: spontaneity and sign
A galvanic cell has a positive standard cell potential and a negative change in Gibbs free energy. The reaction wants to happen; the cell harvests it. Because the anode is the source of electrons flowing out into the circuit, it is labelled negative, and the cathode positive.
An electrolytic cell has a negative standard cell potential and a positive change in Gibbs free energy. An external source forces the reaction. The power supply pulls electrons away from the anode, which is why the anode is now attached to the positive terminal and labelled positive, with the cathode negative.
The relationship connecting these is ΔG° = −nFE°cell, where n is the number of moles of electrons transferred and F is Faraday's constant. A positive cell potential gives a negative ΔG° (spontaneous, galvanic); a negative cell potential gives a positive ΔG° (non-spontaneous, electrolytic). The MCAT asks you to move between these two statements constantly, so it is worth being able to do it in one step.
| Feature | Galvanic (voltaic) | Electrolytic |
|---|---|---|
| Spontaneity | Spontaneous | Non-spontaneous, externally driven |
| E°cell | Positive | Negative |
| ΔG° | Negative | Positive |
| Anode | Oxidation, negative | Oxidation, positive |
| Cathode | Reduction, positive | Reduction, negative |
| Electron flow in wire | Anode → cathode | Anode → cathode |
| Typical example | Battery discharging | Electroplating, electrolysis of water |
Why the anode sign flips — the intuition
Students often memorise the sign table and then lose it under pressure. The intuition is more durable.
In a galvanic cell, nothing is pushing. Electrons pile up at the anode because oxidation is happening there spontaneously, and that accumulation of negative charge is exactly what drives them through the wire. The anode is negative because it is genuinely electron-rich.
In an electrolytic cell, the power supply is doing the pushing. It pulls electrons out of one electrode, and that electrode — now electron-deficient — is where oxidation is forced to occur. It is connected to the positive terminal, so it is labelled positive.
In both cases the label describes the electrode's relationship to the circuit, not the chemistry. The chemistry — oxidation at the anode — never moved.
Concentration cells, the case that looks broken
A concentration cell has the same electrode material and the same species on both sides, differing only in concentration. Its standard cell potential is zero, which makes students conclude no current can flow.
It can. The driving force is the concentration gradient, not a difference in standard reduction potentials, and the system moves toward equal concentrations. Reduction occurs in the more concentrated compartment (removing ions from it) and oxidation in the dilute one (adding ions to it).
The Nernst equation is what makes this quantitative: E = E° − (RT/nF) ln Q, or at 25 °C the convenient form E = E° − (0.0592/n) log Q. With E° = 0, the entire cell potential comes from the log term, and the cell runs until the concentrations equalise and Q approaches 1, at which point E goes to zero and the cell is dead.
This is a favourite MCAT construction because it separates students who memorised a table from students who understand what drives the cell.
The common mistake
The single most common error is moving oxidation to the cathode in an electrolytic cell because the signs flipped. Nothing about the half-reactions changes. Anchor on "An Ox, Red Cat" first, then apply the sign convention as a separate step.
A second common error is reading the sign of E°cell as a statement about rate. It is not. A large positive cell potential means the reaction is strongly favourable thermodynamically; it says nothing about how fast the reaction proceeds. Thermodynamics and kinetics are separate axes throughout MCAT chemistry, and passages will test the distinction.
A third is forgetting that the standard reduction potential is an intensive property. If you double all the coefficients in a half-reaction, the potential does not double — only n changes, which affects ΔG° but not E°.
Finally, watch the salt bridge. In a galvanic cell it maintains electroneutrality by allowing ion migration between compartments; without it, charge builds up and the cell stops almost immediately. Questions sometimes probe this by asking what happens if it is removed.
How this shows up in passages
Electrochemistry passages on the MCAT commonly present a cell diagram with two half-reactions and standard reduction potentials, then ask you to identify the anode, compute the cell potential, or predict the direction of electron flow.
The reliable procedure: the half-reaction with the more positive standard reduction potential occurs as written, at the cathode. The other one reverses and occurs as oxidation at the anode. Cell potential is the cathode's reduction potential minus the anode's reduction potential — and you do not flip the sign of the anode value before subtracting, which is a frequent slip.
Biological passages often bring this in through the electron transport chain, where electrons pass down a series of carriers with increasing reduction potential. The same logic applies: electrons move spontaneously toward higher reduction potential, releasing free energy along the way.
Electroplating and Faraday's law appear less often but are straightforward when they do — the moles of electrons passed equal current multiplied by time and divided by Faraday's constant, and the stoichiometry of the half-reaction converts that to moles of metal deposited.
Practice this on Verbloom
Verbloom's MCAT general chemistry practice includes passage-based electrochemistry questions with worked explanations for each distractor, which is useful here because the wrong answers in this topic are usually one specific confusion rather than random.
If you find yourself reliably picking the choice that swaps the electrodes, that is a diagnosable habit rather than a knowledge gap.
Frequently asked questions
Is the anode positive or negative?
It depends on the cell type. In a galvanic cell the anode is negative, because oxidation there produces the electrons that drive the circuit. In an electrolytic cell the anode is positive, because an external power supply pulls electrons from it. Oxidation occurs at the anode in both cases.
Which way do electrons flow in an electrochemical cell?
Always from anode to cathode through the external wire, in both galvanic and electrolytic cells. Electrons are produced by oxidation at the anode and consumed by reduction at the cathode, so the direction follows from where the half-reactions sit rather than from the electrode signs.
How do I know which half-reaction is the cathode?
In a galvanic cell, the half-reaction with the more positive standard reduction potential runs as a reduction, making it the cathode; the other reverses and becomes the anode. Cell potential is the cathode potential minus the anode potential, using the tabulated reduction values for both without flipping signs first.
How does a concentration cell work if E° is zero?
The driving force is the concentration difference rather than a difference in standard potentials. Reduction occurs in the more concentrated half-cell and oxidation in the dilute one, moving the system toward equal concentrations. The Nernst equation supplies the potential entirely through the reaction-quotient term, and the cell stops once the concentrations equalise.
Does a large cell potential mean a fast reaction?
No. Cell potential is a thermodynamic quantity related to ΔG° through ΔG° = −nFE°cell. It tells you how favourable the reaction is, not how quickly it proceeds. Rate is governed by kinetics, including activation energy and any catalysis, which the passage will address separately if it matters.
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